is it that simple? well i am fascinated
i have found a little clue about your point in a book (fundamental of wimax)
maybe i should try first.
Thank you by the way
At 3:51am on February 10, 2009, Davor Virkes said…
:lol: grossly :lol:
dB-s are representing powers and they are a log form of ratios. In case of dBm-s it is the ratio between a milliwatt ("m" in dBm) and a power in question, so the proper way of handling sums of signals is returning them back to their milliwatt form, add, and a sum is transformed to dBm-s again. There are some easy calculations, as if adding two identical signals - the result is +3dB of the starting value.
Usually only a strongest interferer counts, and the sum of all others is seldom even comparable to it.
First, I'm sorry to put this into your commentary section
Mr. Virkes, I'd like to ask you about WiMAX interference issue.
Right now I'm making System Level Simulation (SLS) for Mobile WiMAX. I kinda have some trouble in calculating interference from other user/BS.
You see that in SLS, we use multiple cell and assume multiple users occupied the entire network.
It turns out that interference is given by:
I = sum(EIRP - Pathloss - otherlosses) (dB)
If there are more than one user, say the I value in average is -100 dB, then if there are 3 users which emit -100dB interference power to the user of interest, then I = -300 dB.....is it true?
Unfortunately not. In fact, I did not need any fancy ASN in our system, just basic L2 connectivity, AAA and stuff. I am not completely illiterate here, but you better seek answers somewhere else ;)
BTW did you notice importance of optimising antenna gain vs height and tilt against a covered distance?
There are optimum combinations of gain/height/tilt that provide you with almost constant signal strength and high C/I in a whole cell.
Think about it ;)
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i have found a little clue about your point in a book (fundamental of wimax)
maybe i should try first.
Thank you by the way
dB-s are representing powers and they are a log form of ratios. In case of dBm-s it is the ratio between a milliwatt ("m" in dBm) and a power in question, so the proper way of handling sums of signals is returning them back to their milliwatt form, add, and a sum is transformed to dBm-s again. There are some easy calculations, as if adding two identical signals - the result is +3dB of the starting value.
Usually only a strongest interferer counts, and the sum of all others is seldom even comparable to it.
First, I'm sorry to put this into your commentary section
Mr. Virkes, I'd like to ask you about WiMAX interference issue.
Right now I'm making System Level Simulation (SLS) for Mobile WiMAX. I kinda have some trouble in calculating interference from other user/BS.
You see that in SLS, we use multiple cell and assume multiple users occupied the entire network.
It turns out that interference is given by:
I = sum(EIRP - Pathloss - otherlosses) (dB)
If there are more than one user, say the I value in average is -100 dB, then if there are 3 users which emit -100dB interference power to the user of interest, then I = -300 dB.....is it true?
or i miscalculated it?
Thank you in advance for your attention and reply
I am rebuilding my home computer and without it all my old contacts are on floppies. Guess what - the new computer has no floppy drive :lol:
I added your contact to Skype, so we may meet there.
I have met soem of them, can u plz give me your details info where u been with them and you cell no.
regards
MS
Check the following link on “WiMAX Professional Seminar 2009, Tehran – Iran”
http://www.wimax360.com/forum/topics/wimax-professional-seminar
I’ll be glad to meet you there.
Best Regards,
Ali
thanx a ton. This is a very useful information. thanks again.
JIMISH
There are optimum combinations of gain/height/tilt that provide you with almost constant signal strength and high C/I in a whole cell.
Think about it ;)
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